How many electrons pass through a lamp in one minute if the current be 220 MA
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Answered by
8
Hey.
Q = I t
So total charge passed in 1 minute
= 220 mA × 1 minute
= 220×10^-3 A × 60 s
= 13.2 C
As charge on 1 electron = 1.602 x 10^-19 C
So, no. of electrons = 13.2 / 1.602 x 10^-19
= 8.2397 × 10^19 electrons .
Thanks.
Q = I t
So total charge passed in 1 minute
= 220 mA × 1 minute
= 220×10^-3 A × 60 s
= 13.2 C
As charge on 1 electron = 1.602 x 10^-19 C
So, no. of electrons = 13.2 / 1.602 x 10^-19
= 8.2397 × 10^19 electrons .
Thanks.
Answered by
0
hope you like it
Q = I t
So total charge passed in 1 minute
= 220 mA × 1 minute
= 220×10^-3 A × 60 s
= 13.2 C
As charge on 1 electron = 1.602 x 10^-19 C
So, no. of electrons = 13.2 / 1.602 x 10^-19
= 8.2397 × 10^19 electrons
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