How many electrons per second pass through a section of wire carrying a current of 0.7A?
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Answer:
The number of electrons will be given as 4.3 *10^19
Explanation:
Since we know that current I is given by I =Q\t;
where Q= total charge
t= total time
Now the total current can also be given as number of electrons multiplied by total charge on one electron, that is, n*1.6*10^-19 ; where n is total number of electrons.
Therefore,
0.7A= Q\1=n* 1.6*10^-19
From the above equation we get,
n=0.7\1.6*10^-19
n=4.3*10^18
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