How many electrons present in calcium with L is equal to zero?
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Explanation:
For s-subshell, l=0 ∴ values of magnetic quantum number is 0. For p-orbital, l=1 ∴ values of magnetic quantum numbers are -1, 0, 1. In calcium, 6 orbitals for which magnetic quantum number is zero. So \[12\left( 6*2 \right)\]electrons whose magnetic quantum number is zero.
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