Question

How many electrons, protons, and neutrons are there in the ion of the hypothetical element scriptbase C x to the power of negative 1 end exponent end scriptbase presubscript 312 presuperscript 729 ?

Answer 1

Explanation:

The number of neutrons and protons are shown below.

Nucleus Atomic number, Z

Mass number, A

Number of protons = atomic number

Number of neutrons =A−Z

6

13

C

6 13 6 13−6=7

8

16

O

8 16 8 16−8=8

12

24

Mg 12 24 12 24−12=12

26

56

Fe 26 56 26 56−26=30

38

88

Sr 38 88 38 88−38=50