Science, asked by Anonymous, 1 year ago

How many electrons should be removed from a coin of mass 1.6g so that it may just flow in an electric field of intensity 10 ki power 9 N/C , directed upward.

Answers

Answered by Anonymous

26

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▶Electric force F due to the field E = q E

F = n e E, as q = n e,

e = magnitude of charge on electron,

n = number of electrons removed.

E = 1 * 10⁹ N/C

Gravity force = m g

m = 1.6 gms

g = 9.8m/s

So n * 1.6 *10⁻¹⁹ * 1* 10⁹ = 1.6 * 10⁻³ * 9.8

n = 9.8 × 10⁷ electrons

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Anonymous: any help?

Answered by suman682

11

E = 1 * 10⁹ N/C

Gravity force = m g

m = 1.6 gms

g = 9.8m/s

So n * 1.6 *10⁻¹⁹ * 1* 10⁹ = 1.6 * 10⁻³ * 9.8

n = 9.8 × 10⁷ electrons

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