How many electrons should be removed from a conductor so that it acquires a positive charge of 3.5 nC ?
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Answer:
n=10
Explanation:
Given
Charge q=3.5×10
−9
Let the nQ of electron to be removed be n
We know that
Q=ne
n=
e
Q
n=
1.6×10
−19
3.5×10
−9
n=2.1875×10
−9+19
n=2.1875×10
10
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