How many electrons should pass through a conductor in 1 second to constitute 1 ampere current ? (charge on an electron = 1.6 *10power -19 C
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Answer:
Q= ne
and Q = It
therefore
Q = it
= 1 coloumb
now
1= n× 1.6 × 10‐¹⁹
1/ 1.6 × 10‐¹⁹
= 10× 10¹⁹ / 16
= 5/ 8 × 10¹⁹
= 0.625 × 10¹⁹
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