how many electrons will constitute 2x10^-6 C of charge
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Q = ne
2×10^-6 = n×1.6×10^-19
n = 1.25×10^13 (n = number of electrons)
2×10^-6 = n×1.6×10^-19
n = 1.25×10^13 (n = number of electrons)
Answered by
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Charge on 1 electron = 1.6 X 10^-19 C (elementary charge)
Total Charge = 2 X 10^-6 C
Therefore Q = ne (Quantisation of charge)
Here n = number of electron, e = elementary charge = 1.6 X 10^-19, Q = Total Charge
2 X 10^-6 C = n (1.6 X 10^-19C)
n = 2 X 10^-6 C/1.6 X 10^-19C
n = 1.25 X 10^13 electrons
Total Charge = 2 X 10^-6 C
Therefore Q = ne (Quantisation of charge)
Here n = number of electron, e = elementary charge = 1.6 X 10^-19, Q = Total Charge
2 X 10^-6 C = n (1.6 X 10^-19C)
n = 2 X 10^-6 C/1.6 X 10^-19C
n = 1.25 X 10^13 electrons
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