how many electrons with (n+1)=8 are present in an atom with atomic number 109?
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17 electrons in an atom can have (n+1)=8
with atomic number 105
Total number of electrons=105
The electron in the outermost shell=5f 14 6d3 7s2
In 5f, by using formula (n+l)=5+3=8
Also the 14 electrons
In 6d,n+l=6+2=8
Also the 3 electrons
So total of 14+3=17 electrons
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