Physics, asked by goclickdukhift, 1 year ago

how many electrons would have to be removed from a coin to leave it with charge pf 10^-7c

Answers

Answered by JunaidMirza
85
Q = ne

Here
- Q = charge
- n = number of electrons
- e = charge of 1 electron

Charge of 1 electron = 1.6 × 10^-19 Coulomb

Number of electrons = 10^-7 Coulomb / (1.6 × 10^-19 Coulomb)
= 625 × 10^9 electrons
= 625 billion electrons

625 billion electrons should be removed from [neutral] coin.
Answered by Elena611
5

Answer:

Explanation:

given data:

= 10^-7 Coulomb

formula used is :

Q = ne

we know

Charge of 1 electron = 1.6 × 10^-19 Coulomb

so,

Number of electrons

= 10^-7 Coulomb / (1.6 × 10^-19 Coulomb)

the ans will be:

= 625 × 10^9 electrons

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