How many electrons would have to be removed from a copper penny to leave it with a positive charge of 10power-7
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n=q/e
=>n=(10^(-7))/(1.6*10^(-19))
=>n=625,000,000,000
=>n=6.25*10^11 electrons
=>n=(10^(-7))/(1.6*10^(-19))
=>n=625,000,000,000
=>n=6.25*10^11 electrons
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