Question

How many electrons would have to be removed when it is charged with 1.0 x 10-6 C?

Answer 1

Answer:

Explanation:

The charge on an electron is 1.6×10−19C. So for part (a) we can determine that the number of electrons would be:

1.0×10−71.6×10−19=6.25×1011 electrons

For part b, we need to know how may electrons are in the penny. The relative atomic mass of copper is 63.546. By definition, 63.546g of copper would contain a number of atoms equal to Avogadro's constant which is 6.02×1023mol−1.

So in 3.11g there would be the following number of atoms:

3.1163.546×(6.02×1023)=2.95×1022 atoms

The atomic number of copper is 29, so a neutral copper atom has 29 electrons.

Hence the fraction of electrons that would need to be removed would be:

6.25×101129×(2.95×1022)=7.31×10−13