Question

How many elements are possible for 1 st periodic table if azimuthal quantum number can have integral values from 0,1,2 (n i)

Answer 1

Given:  Azimuthal quantum number have integral values from 0,1,2 (n + 1)

To find: How many elements are possible for 1 st periodic table ?

Solution:

• Now we have given that Azimuthal quantum number can have value of x from:

                    0 to ( n + 1 )

• So :

                    for n = 1,  l = 0, 1, 2  

                    for n = 2, l = 0, 1, 2, 3

• Now we have (n+l) rule, so applying it , we get the sub shell  

• The order being

                    1s, 1p , 2s, ...

• Total Number of such element possible will be:

                    2 x  ( capacity of 1s subshell ) + 6 x ( capacity of 1p subshell )

                    = 8 elements

Answer:

           So 8 elements are possible for 1 st periodic table.