Question

How many enery will be released in joule due to the mass defect in 1 gram?

Answer 1

e = mc^2

m = 1g = 0.001 kg = 10^-3 kg

c = 299792458 m/s

so, e = 10^-3 * 299792458 * 299792458

so, e = 89875517873681.764 joules

which can be rewritten as

e = 89.875517873681764 terajoules (21480.764 tons of TNT)

which is approximately