Question

How many equivalent of hypo is oxidized by one mole iodine

Answer 1

Answer:

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The equivalent weight of Na2S2O3 in the reaction is 2Na2S2O3+ ...

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... weight / number of electron per mole transfer during the reaction.

Answer 2

2Na2S2O3 +I2 =2NaI +Na2S4O6

Here, oxidation no. of Na2S2O3 =+2

And Na2S4O6 =+2.5

Here, Na2S2O3 has 2 mole and sulphur is 4 then oxidation no. of Na2S2O3 is 4×2=8

In product side Na2S4O6 has 1 mole and sulphur element is 4 then the oxidation. No is 4×2.5=10

The difference of exchanged electron is 10-8=2

The equivalent weight of Na2S2O3 is = molecular weight of Na2S2O3/n factor

N factor= no of exchanged electron /no of moles

The equivalent weight of Na2S2O3=158×2/2=158