Question

How many equivalents of solute are contained in 1L of 0.5N solution

Answer 1

Explanation:

normality = n eq/volume

Answer 2

${\huge{\bf{\underline{\red{Answer}}}}}$

Normality = Number of equivalents of solute/Volume

$1 = \frac{number \: of \: equivalent \: }{0.5}$

Number of equivalents :-

$= 0.5$