How many even number in 100 to 200
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tn=a+(n-1)d
200=100+(nā1)2
200-100=(n-1) 2
100=(n-1) 2
100/2=n-1
50=n-1
50+1=n
n=51
thus there are 51 even number between 100 to 200..
hope it helps you!
200=100+(nā1)2
200-100=(n-1) 2
100=(n-1) 2
100/2=n-1
50=n-1
50+1=n
n=51
thus there are 51 even number between 100 to 200..
hope it helps you!
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