How many even numbers greater than 300 can be formed with the digits 1, 2, 3, 4, 5 if repetition of digits in a number is not allowed?
Answers
Answer:
111 Numbers
Step-by-step explanation:
even numbers greater than 300
5 Digit Even numbers
4 Digit Even Number
3 Digit Even Numbers > 300
3 Digit Even Numbers > 300
1st Digit - 3 2nd digit 1 , 4 , 5 3rd digit 2 = 3 Ways
1st Digit - 3 2nd digit 1 , 2, 5 3rd digit 4 = 3 Ways
1st Digit - 4 2nd digit 1 , 3 , 5 3rd digit 2 = 3 Ways
1st Digit - 5 2nd digit 1 , 3 , 4 3rd digit 2 = 3 Ways
1st Digit - 5 2nd digit 1 , 2, 3 3rd digit 4 = 3 Ways
= 15 Ways
4 Digit Even Number
4th Digit : 2 1st 2nd & 3rd Digit can be ⁴P₃ = 24 Ways
4th Digit : 4 1st 2nd & 3rd Digit can be ⁴P₃ = 24 Ways
= 48 ways
5 Digit Even Number
5th Digit : 2 1st 2nd , 3rd & 4th Digit can be ⁴P₄ = 24 Ways
5th Digit : 4 1st 2nd , 3rd & 4th Digit can be ⁴P₄ = 24 Ways
= 48 Ways
total number = 48 + 48 + 15
= 111
Answer:
111 ways
Step-by-step explanation:
In this question,
We need to find the numbers greater than 300 can be formed with the digits 1,2,3,4,5 an repetition of digits in a number is not allowed.
Even numbers greater than 300
5 Digit Even numbers
4 Digit Even Number
3 Digit Even Numbers greater than 300
3 Digit Even Numbers greater than 300
1st Digit - 3 2nd digit 1 , 4 , 5 3rd digit 2 = 3 Ways
1st Digit - 3 2nd digit 1 , 2, 5 3rd digit 4 = 3 Ways
1st Digit - 4 2nd digit 1 , 3 , 5 3rd digit 2 = 3 Ways
1st Digit - 5 2nd digit 1 , 3 , 4 3rd digit 2 = 3 Ways
1st Digit - 5 2nd digit 1 , 2, 3 3rd digit 4 = 3 Ways
= 15 Ways
4 Digit Even Number
4th Digit : 2 1st 2nd & 3rd Digit can be ⁴P₃ = 24 Ways
4th Digit : 4 1st 2nd & 3rd Digit can be ⁴P₃ = 24 Ways
= 48 ways
5 Digit Even Number
5th Digit : 2 1st 2nd , 3rd & 4th Digit can be ⁴P₄ = 24 Ways
5th Digit : 4 1st 2nd , 3rd & 4th Digit can be ⁴P₄ = 24 Ways
= 48 Ways
Total number = 48 + 48 + 15
= 111 ways