Question

How many even numbers of 3 digits can be formed when repetition of digits is allowed?​

Answer 1

Explanation:

As the repetition is allowed, So the number of digits available for X = 6, Similarly, the number of digits available for Y = 6. Thus, The total number of 3-digit even numbers that can be formed = 6×6×3 = 108.

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Answer 2

Answer:

A three digit even number is to be formed from given 6 digits 1,2,3,4,5,6.

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Since, for the number is to be even , so ones place can be filled by 2,4 or 6. So, there are 3 ways to fill ones place.

Since, repetition is allowed , so tens place can also be filled by 6 ways.

Similarly,hundreds place can also be filled by 6 ways.

So, number of ways in which three digit even numbers can be formed from the given digits is 6×6×3=108