Question

How many even numbers of four digits can be formed with digits 0, 1, 2, 3, 4, 5 and 6; no digit being used more than once?

Answer 1

Answer:

see in the first place we cannot use 0 so the no of options available are 6

in the second and third place all numbers are possible so no of possible ways =7*7

in the fourth place only 4 digits are available i.e 2,0,4,6

so total ways =7*7*6*4=1176

please mark it as the brainliest answer

Answer 2

Answer:

Step-by-step explanation:

My attempt to solve this problem is:

First digit cannot be zero, so the number of choices only 6(1,2,3,4,5,6)The last digit can be pick from 0,2,4,6, so the number of choices only 4

Second digit can be only pick from the rest, so the number of choices only 5

Third digit can be only pick from the rest, so the number of choices only 4The total number of choices is 6⋅4⋅5⋅4=480

i hope i helped you