Question

how many excess electron must be removed from a body to give it a +ve charge of 1.0×10^-8 C?​

Answer 1

Answer:

Q=1×10^6C

charge on electron=1.6×10^-19C

As Q=ne

where n is no of electrons

n=Q/e

n=1×10^6/1.6×10^-19

n=0.625×10^25

n=625×10^22 electrons

Answer 2

Answer:

6.25*10^10

Explanation:

since q= ne,

here, q= 1.0*10^-8

e =1.6*10^-19 so

n =1.0*10^-8 /1.6*10^-19

hence n= 6.25*10^10