How many excess electrons must be placed on each of two small spheres spaced 3 cm apart if the force of repulsion between the spheres is to be 10^-19?.
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Answer:
ANSWER
Force between the two electrons,
F=
4πϵ
0
1
×
d
2
(ne)(ne)
or n
2
=
e
2
F×4πϵ
0
×d
2
n
2
=
(1.6×10
−19
)
2
10
−19
×
9×10
9
1
×(3×10
−2
)
2
=(625)
2
or n=625
∴ The number of electrons placed on each of the sphere =625.
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