How many excess electrons must be removed from abody to give it a positive charge of 1.0 × 10^-8 C.
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Answer:
6.25*10^10c.
Explanation:
since q = ne,
here, q = 1.0*10^-8
e 1.6*10^-19 so
n=1.0*10^-8/1.6*10^-19
hence n= 6.25*10^10c.
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