Question

how many excess electrons must ne removed from a body to give it a positive chrge of 1.0×10-8​

Answer 1

Answer: Number of electrons to be removed = 6.25 * 10^10

Explanation:

No. of electrons removed = No. or protons added (positive charge)

Hence,

Charge on body (q) = 1.0 * 10^-8

Charge of electron (e) = 1.6 * 10^-19

No. of electrons (n) = to be calculated

q = n * e

1.0 * 10^-8 = n * 1.6 * 10^-19

n = (1.0 * 10^-8)/1.6 * 10^-19

n = 1.0 * 10^19 - 8/ 1.6

n = (1.0 * 10^11)/1.6

n = 0.625 * 10^11

n = 6.25 * 10^10

Number of electrons to be removed = 6.25 * 10^10

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