How many faraday of electricity are required to produce 18g of aluminium?
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AlCl3 → Al3+ + 3Cl–
Al3+ + 3e– → Al
1 mole of Al requires passage of 3 mole of electrons. Charge on 3 mole of e– is 3 Faraday.
Moles of Al produced = Mass of Al/Molar mass of Al
= 18/27 = 0.66 Moles
3F of electricity produces 1 mole of Al.
:. Number of Faradays of electricity required to produce 0.48 moles of Al
= 0.66x 3
= 1.98Faraday.
Al3+ + 3e– → Al
1 mole of Al requires passage of 3 mole of electrons. Charge on 3 mole of e– is 3 Faraday.
Moles of Al produced = Mass of Al/Molar mass of Al
= 18/27 = 0.66 Moles
3F of electricity produces 1 mole of Al.
:. Number of Faradays of electricity required to produce 0.48 moles of Al
= 0.66x 3
= 1.98Faraday.
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