How many faradays are needed for reduction of 2.5 mole cr2o7 to cr?
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Cr (VI) gets converted to Cr(III) i.e.
Cr 6+ + 3e- ---------> Cr3+
so there are 3 electrons involved in the reaction
so ANS= 3Faraday
therefore to reduce 2.5 mole cr2o7 we require 6x2.5 faraday of electrons
Cr 6+ + 3e- ---------> Cr3+
so there are 3 electrons involved in the reaction
so ANS= 3Faraday
therefore to reduce 2.5 mole cr2o7 we require 6x2.5 faraday of electrons
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