How many faradays are required to reduce 1 mole of bro3- to br-?
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9
Answer:
3
Explanation:
1 mol contains 6.023*10^{23} atoms.
Charge required to reduce 1 mol Br^{3+} to Br is
3*6.023*10^{23}*1.602*10^{-19}=3*96500\;Coulombs .
We know 96500 \;Coulombs which is equal to 1 Faraday . The number of Faradays required is \frac{3*96500}{96500} =3\;Faradays .
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