How many faradays of electricity required to electroplate 0.5 moles of Ag from silver nitrate solution (at mass Ag 108)
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Answer:
3.37232 × 10^24
Explanation:
NO. of electrons in 0ne mole of silver = 56 × avogadro contant
56 × 6.022 × 10^23
here no. of moles of silver = given mass ÷ molar mass
10.8 ÷ 108 = 0.1 moles
so no. of electrons in 0.1 moles if Ag = 0.1 × 56 × 6.022 × 10^23
3.37232 × 10^24
Explanation:
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