How many five digit number can be formed from 1,2,3,4,5 without reptition when the digit at the units place must be greater than that in the tens place
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mujhe question samajh me ni aa rha
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when we take 1 as tenth place digit then in units place 2,3,4,5 can be used satisfying the condition.
so leftmost three digits(as it is non repetitive)can be combined into 3! way
total ways=4*3!
for 2=>>3*3!
for 3=>>2*3!
for4=>>1*3!
therefore total numbers will be=(4+3+2+1)*3!=60
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