Question

How many five digit numbers can be formed using 0,1,2,3,4,5 which is divisible by 4

Answer 1

1, 3, 5, 2,4,0
for five digit number
=3! ×2! +3! ×2! ×3! ×2!
=12×3
=36

another method is
3! ×3! =36


we can these digits because 1, 3, 5 never come in 4 table so for them use 3!

another is 2, 4, 0
comes in 4 table so for them use 3!

Answer 2

I am just giving you a hint because I hope so you can do it
First step:

We should determine which 5 digits from given 6, would form the 5 digit number divisible by 3.

We have six digits: 0,1,2,3,4,5. Their sum=15.

For a number to be divisible by 3 the sum of the digits must be divisible by 3. As the sum of the six given numbers is 15 (divisible by 3) only 5 digits good to form our 5 digit number would be 15-0={1, 2, 3, 4, 5} and 15-3={0, 1, 2, 4, 5}. Meaning that no other 5 from given six will total the number divisible by 3.

Second step:

We have two set of numbers:
{1, 2, 3, 4, 5} and {0, 1, 2, 4, 5}. How many 5 digit numbers can be formed using this two sets:

{1, 2, 3, 4, 5} --> 5! as any combination of these digits would give us 5 digit number divisible by 3. 5!=120.

{0, 1, 2, 4, 5} --> here we can not use 0 as the first digit, otherwise number won't be any more 5 digit and become 4 digit. So, total combinations 5!, minus combinations with 0 as the first digit (combination of 4) 4! --> 5!-4!=96

120+96=216
I hope so it can be helpful to you
please select my answer as brainliest answer