How many flip-flops are required to make a mod-32 binary counter?
Answers
For a mod N counter, the number of flip-flops that are required is less than or equal to 2 to the power 'n', where n is a positive integer, i.e. N ≤ 2ⁿ.
Therefore, for a mod 32 counter, it can be calculated as:-
32 = 2⁵, where n = 5
So, 5 flip-flops are required to make a mod-32 binary counter.
For a mod N counter, the number of flip flops required is less than or equal to 2 raised to power n where n is a positive integer.
The equation for that will be:
N<= 2^n
Hence,
For a mod 10 counter, 10< 2^4. So 4 flip-flops are required.
For a mod 16 counter, 16=2^4. So again 4 flip-flops are required.
For a mod 32 counter, 32=2^5. So 5 flip-flops are required.
The meaning of Mod -10 is that the number of states will be 10 which means it will be from 0-9 and if we talk about Mod-16 it will be from 0-15.