How many four digit numbers are there such that when they are divided by 101, they have 99 as
remainder?
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Heya.......!!!!
We can solve this question by Airthmetic Progession .
=> For applying the formulae [a(n) = a + (n-1)d]
we should have d .
Taking out maximum and minimum value as of the question , it's given that 4 digit number
=>> 1008, 1109,.............. 9997
here we get ,,
=> a = 1008
=> d = 101
=> a(n) = 9997
Putting the values in formulae :
9997 = 1008 + (n - 1) 101
8989 = (n - 1) 101
89 = n - 1
n = 90.
90 is the required answer .
Hope It Helps u ^_^
We can solve this question by Airthmetic Progession .
=> For applying the formulae [a(n) = a + (n-1)d]
we should have d .
Taking out maximum and minimum value as of the question , it's given that 4 digit number
=>> 1008, 1109,.............. 9997
here we get ,,
=> a = 1008
=> d = 101
=> a(n) = 9997
Putting the values in formulae :
9997 = 1008 + (n - 1) 101
8989 = (n - 1) 101
89 = n - 1
n = 90.
90 is the required answer .
Hope It Helps u ^_^
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