how many four digit numbers contain no 2
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Total number of 4 digit numbers=9000(i.e1000 to 9999)
We try to find the number of numbers not having digit 2 in them.
Now consider the units place,it cam be selected in 9 ways(i.e0,1,3,4,5,6,7,8,9)
Tens place can be selected in 9 ways(i.e0,1,2,3,4,5,6,7,8,9)
Hundreds place can also be selected in 9 ways(i.e0,1,2,3,4,5,6,7,8,9)
Thousands place can be selected in 8 ways(i.e1,3,4,5,6,7,8,9),here 0 can't be taken
Total number of numbers not having digit 2 in it=9×9×9×8=5832
Total number of numbers having digit 2 in it=9000-5832=3168....
Hope it helps❤
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