How many four-digit numbers, each divisible by 4 can be formed using the digits 5, 6, 7, 8, 9, repetition of digits being allowed in any number?
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Step-by-step explanation:
_ _ _ _
these are the places to fill the digits
In order to be divisible by 4 the last two digits must be divisible by 4
so let us take the combinations of last two numbers
they can be: 56,68,76,88,96.
so the last two digits have 5 ways
the first two places can be any of these given numbers so the first place can be filled in 5 ways and second place can be filled in 5 ways
total ways=5*5*5=125
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