Math, asked by jayanthchennoju, 10 months ago

How many four-digit numbers, each divisible by 4 can be formed using the digits 5, 6, 7, 8, 9, repetition of digits being allowed in any number?

Answers

Answered by venkatavineela3
2

Answer:

Step-by-step explanation:

_ _ _ _

these are the places to fill the digits

In order to be divisible by 4 the last two digits must be divisible by 4

so let us take the combinations of last two numbers

they can be: 56,68,76,88,96.

so the last two digits have 5 ways

the first two places can be any of these given numbers so the first place can be filled in 5 ways and second place can be filled in 5 ways

total ways=5*5*5=125

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