How many four digits even numbers with distinct digits can be formed out of the digits 0,1,2,3,4,5,6 ?
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This is one of the Basic question on Permutation and Combination.
Well this one deals with Permutation .
Lets check how to solve this:
consider: abcd to be a 4 digit number now lets fill in all possibilities to check how many numbers we can form.
d can be 0,2 or 6 (only then is abcd even!)
c can take any value(0,1,2,3,5,6 except the value we filled at d).No repetition
similarly:
b can take any value(0,1,2,3,5,6 except the value we filled at d and c)
a can take any value(0,1,2,3,5,6 except the value we filled at d,c and b)
Therefore we can have 3*5*4*3=180 numbers possible(3-d,5-c,4-b,3-a)!
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