Question

How many four digits no can be formed with 0 1 2 3 4 5 which is dibisible by5?

Answer 1

First number 'a' = 1025
Last number 'am or l' = 5430
Common difference 'd' = 5

FORMULA
an = a + (n - 1) d
Subsitute
5430 = 1025 + (n - 1) 5
5430 - 1025 = 5 (n - 1)
4405 = 5 (n - 1)
4405 / 5 = n - 1
881 = n - 1
881 + 1 = n
882 = n

Therefore, their are 882 four digits numbers is formed with 0, 1, 2, 3, 4, 5 which is dibisible by 5.