Question

How many g of dibasic acid (mol. weight 200)
should be present in 100 ml. of the aqueous
solution to give strength of 0.1 N?
(1) 10 g
(2) 29
(3) 1 g
(4) 20 g​

Answer 1

Answer:

quivalent wt. of dibasic acid = mol. wt/2 = 200/2 = 100 Strength = 0.1 N, m = ? , V = 100 mL then, m = EVN/1000 = (100 x 100 x 0.1)/1000 = answered this

Equivalent weight of solute = 200/2=100 N= wt. of solute in grams*1000/Equivalent wt. Of solute *volume (ml) 0.1 =wt. Of solute in grams *1000/100*100 Wt. Of solute in grams =0.1*100*100/1000

if it was helpful pls rate me as brainliest