Question

how many g of H2O are present in 0.25 mole of it​

Answer 1

Answer:

4.5 grams

Explanation:

The total mass of 1 mole of water molecule is 18g.So to find the mass of 0.25 moles requires just a multiplication 18 with 0.25.

Answer 2

Answer: 4.5 grams.

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number $6.023\times 10^{23}$ of particles.

1 mole of water weighs equal to the molecular mass of water.

1 mole of water weigh= 18 g

Thus 0.25 moles of water weigh=$\frac{18}{1}\times 0.25=4.5g$

Thus the amount of $H_2O$ present in 0.25 mole of it​ is 4.5 grams.