Question

How many g of hydrogen chloride, HCL
are required to prepare 4l of 5Molar HCL in water​

Answer 1

we know that

$\underline \bold\green{molarity = \frac{moles \: of \: soute}{volume \: of \: sol {}^{n}in \: l } }$

$5 = \green{ \frac{moles} {4}}$

moles =20

$also \\ \underline \bold\blue{moles = \frac{wt}{molecular \: wt} }$

$20 = \frac{wt}{36.5}$

$\underline \bold\red{wt = 20 \times 36.5 = 730g}$

Answer 2

Answer:

730 g

Explanation:

this is the answer for this question