Chemistry, asked by janyben1998, 2 days ago

How many GAM present in 80g O2?

Answers

Answered by mantasharahman375

0

Explanation:

Atomic mass of oxygen is 16 and 16g oxygen = 1 mole oxygen atom

Therefore molecular mass of oxygen = 2×16g= 32g

32g of oxygen =2× 6.023×10^23 no.of atoms

Therefore,80g of oxygen = 80×2×6.023×10^23/32 = 3.0115×10^24 no.of atoms

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