How many gm of Na2Co3 are required to prepair 250 ml N/10 Na2Co3
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Equivalent weight of Na2CO3 is 106/2 = 53 g
N = (w / GEW) * 1000 / V_ml
w = N * GEW * V_ml / 1000
= 0.1 * 53 * 250 / 1000
= 1.325 g
Weight of Na2CO3 required is 1.325 g
N = (w / GEW) * 1000 / V_ml
w = N * GEW * V_ml / 1000
= 0.1 * 53 * 250 / 1000
= 1.325 g
Weight of Na2CO3 required is 1.325 g
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