how many gram atom and no of atom are there in 224.4g of cu
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#No. of gram atoms of Cu = given gm mass of Cu / atomic mass of Cu
➡ = 224. 4 gm / 63 .54 gm
➡ = 3.53 gram atoms of Cu
# Now let's calculate no. of atoms present in
224.4 gm of Cu
No. of atoms present in 224.4 gm of Cu is equals to
➡ = [224.4 / 63.54 ] ✖ 6.022* 10 ^23
➡ = 21.3 * 10^23 .
#Hence answer of given question is that no. gram atoms are 3.53 ND no. of atoms present in 224.4 gm of Cu are 21.3 *10^23 atoms. #
I hope this will help you friend.
➡ = 224. 4 gm / 63 .54 gm
➡ = 3.53 gram atoms of Cu
# Now let's calculate no. of atoms present in
224.4 gm of Cu
No. of atoms present in 224.4 gm of Cu is equals to
➡ = [224.4 / 63.54 ] ✖ 6.022* 10 ^23
➡ = 21.3 * 10^23 .
#Hence answer of given question is that no. gram atoms are 3.53 ND no. of atoms present in 224.4 gm of Cu are 21.3 *10^23 atoms. #
I hope this will help you friend.
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