Question

how many gram atom and no of atoms are there in 72.52 g of pb

Answer 1

Atomic weight of Pb = 207 g/mol
Given, weight of Pb = 72.52 g
Therefore, Number of moles = 72.52/207
= 0.35 mole
Therefore, number of atoms in 72.52 g = 6.022 x 10^23 x 0.35
= 2.1 x 10^23 atoms

Gram atom for 1 atom = 207/6.022 x 10^ 23
= 3.44 x 10^ -22 g for 1 mole
Therefore for 72.52g Pb Gram atom =
3.44 x 10^-22 x 2.1 x 10^23
= 72.24g

Answer 2

(1) gram atoms are equals to no. moles


(2)if we have to calculate number of atoms present in atom then simply multiply Avogadro number (NA) to its given number of moles or gram atoms of given atom .

atomic mass of pb is 207 gm

Hens number of Gram atoms in pb are equals to ➡= 72 .52 / 207 = 0.35 gm atoms help number of atoms in pb are equals to
➡ = 0.35 ✖ 6.022 *10 ^23 = 2.1 *10^ 23 atoms
⏩⏩ Hens number of Gram atoms in pb
= 0.35 ND no. of atoms in pb are = 2.1 * 10^23 .

# I hope u got it well.