How many gram of acetone must be dissolve in 2.5 kg of water to make 1.60m solution acetone
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Answer:ΔT
f
=iK
f
m
Here, ΔT
f
= lowering in freezing point of water =7.500C
i= Van't Hoff factor =1.87
K
f
=1.860C/m
m=molality
Putting the values of known variables to find m,
m=
iK
f
ΔT
f
=
1.87×1.86
7.5
=2.156
m= molality =
mass of water in kg
number of moles of NaCl
number of moles of NaCl=
molar mass of NaCl
mass of NaCl
=
58.5
mass of NaCl
m=
0.065
mass of NaCl/58.5
mass of NaCl=m×0.065×58.5=2.156×0.065×58.5
mass of NaCl=8.199g
Explanation:
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