Question

How many gram of Ag will be deposited if 5 F quantity of electricity is passed through aqueous solution of AɡNO₃?
1 point

Answer 1

Answer:

540g

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Explanation:

Ag⁺+e⁻→Ag

⇒One faraday of charge is the magnitude of the charge of one mole of electrons

⇒hence,5 F quantity of electricity is passed 5 mole electrons are generated

⇒1 mole of Ag⁺requires 1 mole of electrons

⇒hence 5 moles of Ag is deposited

⇒molecular weight of silver=108g/mol

⇒mass of Ag deposited=108*5=540g