how many gram of calcium hydroxide are needed to make 500ml of 0.125M solution
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Explanation:
to produce 1.5 L of 0.25 M solution ,
moles of calcium hydroxide needed are =
0.25
⋅
1.5
= 0.375 mol
now amount of calcium hydroxide in grams needed can be calculated by multiplying moles by molar mass :
0.375
⋅
74
= 27.75 gm
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