Question

how many gram of co2 and H2O will be for combustion of 290gm of butane find my soichiometry​

Answer 1

Answer:

We have 100g/(58.1g/mole) = 1.72 moles of butane. Multiply the moles of butane by the molar ratio of CO2/C4H10 (4) to find out many moles of CO2 are produced. If all the butane is combusted (we have plenty of O2), we'll produce 6.88 moles of CO2.

Answer 2

Answer:

heat of combustion is the amount of heat evolved when one mole of the substance is completely burnt in air or oxygen.

C

4

H

10

(g)+

2

13

O

2

(g)⟶4CO

2

(g)+5H

2

O(l);ΔH=−2878kJ

In the above reaction, 1 mole of butane undergoes combustion. Hence, ΔH is the heat of combustion of butane gas.

Explanation:

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