how many gram of co2 and H2O will be for combustion of 290gm of butane find my soichiometry
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0
Answer:
We have 100g/(58.1g/mole) = 1.72 moles of butane. Multiply the moles of butane by the molar ratio of CO2/C4H10 (4) to find out many moles of CO2 are produced. If all the butane is combusted (we have plenty of O2), we'll produce 6.88 moles of CO2.
Answered by
2
Answer:
heat of combustion is the amount of heat evolved when one mole of the substance is completely burnt in air or oxygen.
C
4
H
10
(g)+
2
13
O
2
(g)⟶4CO
2
(g)+5H
2
O(l);ΔH=−2878kJ
In the above reaction, 1 mole of butane undergoes combustion. Hence, ΔH is the heat of combustion of butane gas.
Explanation:
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