Question

How many gram of h3po4h3po4 would be needed to neutralise 100 gm of mg(oh)2mg(oh)2?

Answer 1

Here is the answer---

→→→→→→→→→

Reaction for the above Conditions will be ⇒

 3 Mg(OH)₂ + 2H₃PO₄ ---→  Mg₃(PO₄)₂ + 6H₂O

Molar Mass of Mg(OH)₂ = 58 grams/mole.

Mass of Mg(OH)₂ = 100 grams.

Molar Mass of H₃PO₄ = 98 grams/mole.

Now,

From the Equation,

 ∵ 3 × 58 grams of Mg(OH)₂ required to neutralize 2 x 98 grams of Phosphoric Acid.

∴ 1 grams------------------------------196/174 grams of Phosphoric acid.

∴ 100 grams---------------------------(196/174) × 100 grams of phosphoric acid.

                                       = 112.64 grams.

Thus, Mass of the Phosphoric acid required to Neutralize 100 grams of Magnesium Hydroxide is 1123.64 grams.

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