Question

How many gram of HNO, is required to prepare 400 mL solution of 0.2 MB
(1) 5.04 g
(2) 5040 g
(3) 25.2g​

Answer 1

"Answer: (1) 5.04 g

Molar mass of HNO3 = (1+14)+(16x3) = 63g/mol

0.2M means 0.2 moles in 1000ml

Thus, 400ml will contain = 400/1000 x 0.2 = 0.08 moles

Mass of HNO3 = Molar mass x no. of moles

                        = 63 x 0.08 = 5.04g

"