Question

how many gram of hydrogen will be produced when 130.8 gram of zinc is allowed to react with dilute sulphuric acid?(Zn=65.4)

(answer in long type)​

Answer 1

Answer:

Zn(s) + 2HCl(aq)→ ZnCl2(aq) + H2(g)

1 mole of Zn reacts with 2 moles of HCl to produce 1 mole of hydrogen.

The atomic mass of Zn is 65.4 g/mol. The molar mass of HCl is 36.5 g/mol.

When we divide mass with atomic/molar mass, we get number of moles.

Number of moles of Zn = 65

_____=0.994 moles.

65.4

Number of moles of HCl =36.565=1.78  moles.

0.994 moles of Zn will react with 2×0.994=1.988  moles of HCl however only 1.78 moles of HCl are present. Hence, HCl is the limiting reactant.

1.78 moles of HCl will produce 21.78=0.89 moles of H2.

The molar mass of H2 is 2 g/mol.

Mass of H2 obtained = 2g/mol × 0.89mol = 1.78g = 1.8g

Step-by-step explanation:

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